Where's the word_count error...

# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.

def word_count(word):
  lower_word = word.lower()
  split_word = lower_word.split()
  count=0
  if value in split_word:
    count+=1
    result.update({'value':count})
    return result