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Java Java Basics Using your New Tools Coding the Prototype

Posted by El Joven
El Joven
Courses Plus Student 353 Points

Which is the difference between this codes?

This is the teacher's code:

import java.io.Console;

public class TreeStory {

    public static void main(String[] args) {
      //Variables and constants
    Console console = System.console();
    String name = console.readLine("Enter a name:  ");
    String adjective = console.readLine("Enter an adjective:  ");
    String noun = console.readLine("Enter a noun:  ");
    String adverb = console.readLine("Enter an adverb:  ");
    String verb = console.readLine("Enter a verb ending with -ing:  ");

      //Actions
      console.printf("Your TreeStory:\n-----------------\n");
      console.printf("%s is a %s %s. ", name, adjective, noun);
      console.printf("They are always %s %s.\n", adverb, verb);
    }
}

And this is my code:

import java.io.Console;

public class TreeStory {

    public static void main(String[] args) {
      //Variables and constants
    Console console = System.console();
    String name = console.readLine("Enter a name:  ");
    String adjective = console.readLine("Enter an adjective:  ");
    String noun = console.readLine("Enter a noun:  ");
    String adverb = console.readLine("Enter an adverb:  ");
    String verb = console.readLine("Enter a verb ending with -ing:  ");

      //Actions
      console.printf("Your TreeStory:\n-----------------\n");
      console.printf(name + " is a " + adjective + " " + noun + "\n");
      console.printf("They are always " + adverb + " " + verb + " " + "\n");
    }
}

Well, I mean, in the end, my code has some disadvantage or something? Because in the "Challenge task" does not accept my code :(

2 Answers

Wesley Seago
Wesley Seago
10,424 Points
Wesley Seago
Wesley Seago
10,424 Points

The "difference" between the two snippets would be that the teacher's code correctly uses string formatting, and your code uses string concatenation. String formatting is much easier to localize than concatenation.

Joshua Katigbak
PLUS
Joshua Katigbak
Courses Plus Student 4,174 Points
Joshua Katigbak
Joshua Katigbak
Courses Plus Student 4,174 Points

Use println() rather than printf as printf is a formatter which will read the input looking for (%)conversion flags. So \n with printf reads as \n rather than a new line. Whereas using \n would be dependent on which OS you are running (Windows uses \r\n for example).