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# While and Repeat While

I was playing around in x code with While and Repeat While and the following let me a little confused. If someone could explain the results to me I would really appreciate it:

so sample 1:

var x = 0

while x <= 20 { print (x) x ++ }

by doing this, it shows in Xcode that the loop runs 21 times. first with 0 through to 20 and prints. Simple enough and that makes sense to me.

Sample 2, I switched the x++ first before print. Thoughts were that it would run 20 times as it would add to x first and then determine it was less than 20 and then print. Code as follows:

var x = 0 while x <= 20 { x ++ print (x) }

the results surprised me. It still ran 21 times, and it printed the numbers 1 - 21. My questions is why would it print the number 21? I thought that it would hit 20 add the 1 and then wouldn't print as it wasn't <= 20. However it did print it.

Thank you to anyone who can give me some help. STAFF

Well let's take a look at that again:

```var x = 0
while x <= 20 {
x ++
print (x)
}
```

Let's say that you're on the very last loop. `x` is now equal to 20. It's still going to run. And what's going to happen? First it's going to increment `x`. So `x` is now equal to 21. And now it prints `x`, which is 21 And there you go! I think maybe the thing you might be confusing here is that it only reevaluates `x` after it gets to the bottom of the code in the loop. It does not reevaluate the original condition at every change of `x`. It waits until it gets up to the top and does the evaluation again with the current value of `x`.

check this out you might understand

var x = 0 x++ while x <= 20 { print (x) }

Thank you for giving me another way to look at it Sandeep.

you're welcome Andrew.

Thank you for your help Jennifer. You're right about where I was confused. I thought it would reevaluate in the loop, so on the last loop where it's 20, I had thought that it would notice the number now being 21 and not printing as it does not meet the case of being <= 20. Andrew Reynolds you're quite welcome! 