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iOS Swift Basics (retired) Control Flow While and Do-While Loop

while loop

Given an array of numbers, print out each number in the array using a while loop and the println statement.

while_loops.swift
let numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
while numbers 1...10 {
println(["1, 2, 3, 4, 5, 6, 7, 8, 9, 10"])
}

4 Answers

Lukas Smith
Lukas Smith
4,026 Points
let numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

var index = 0

while index < numbers.count {
  println(numbers[index])
  index++
}

Still not working

Lukas Smith
Lukas Smith
4,026 Points

try replace println(numbers) on println(index)

You need to make index a variable so that it may be modified...

let numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

var index = 0

while index < numbers.count {
  println(numbers[index])
  index++
}

I think there are some minor issues with this one that needs correction. I would be glad if you can go over it. Thanks

Michael, you are absolutely right. I have corrected the answer... sorry about that, and thanks for catching it. Great job.

Lukas Smith
Lukas Smith
4,026 Points

println("(numbers)")

It didn't work.

Thank you very much.