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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Jason Gabianelli
Jason Gabianelli
1,002 Points

While loop and even or odd

I am having trouble figuring out what is wrong with my code. I think it has something to do with my if statement but I'm not sure.

even.py 
import random



def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5
while start != 0:
    numb = random.randint(1, 99)
    if numb == even_odd:
        print("{} is even").format(numb)
    else:
        print("{} is odd").format(numb)
    start = start - 1

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi Jason! You're doing great, but there are a few problems here. First, you're comparing numb to even_odd. But even_odd is a function that takes one argument and you're not passing in anything. Also, the value returned by the function is not a number but rather a boolean value. It will return true if the number is even and false if it is odd.

Secondly, there is a syntax error in your print statements and the closed parenthesis you have in the middle should be moved to the end.

Take a look:

start = 5  #set start to 5
while start != 0:  #while start is not equal to 0
    numb = random.randint(1, 99)  #get a random number between 1 and 99
    if even_odd(numb):  #send the number into the function and check if it's even
        print("{} is even".format(numb))  #print the number is even
    else:   #if the number is odd
        print("{} is odd".format(numb))  #print the number is odd
    start = start - 1  #decrement start

Hope this clarifies things! :sparkles:

Jason Gabianelli
Jason Gabianelli
1,002 Points

Thank you very much! I've been stuck the past day and this really helped