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Start your free trialJiten Mehta
Front End Web Development Techdegree Graduate 21,209 PointsWhy can't i use a arrow function for the Checkstatus function?
Hey guys, question regarding the checkStatus function...
Here is how i written it initially.
const checkStatus = (response) =>{
if(response.ok){
return Promise.resolve(response)
} else{
return Promise.reject(new Error(response.statusText))
}
}
After creating the Promise.all method i kept getting errors for the checkstatus function.
I then realized Guil has been using normal function syntax.
I then changed the checkStatus function to the following...
function checkStatus(response) {
if(response.ok){
return Promise.resolve(response)
} else{
return Promise.reject(new Error(response.statusText))
}
}
After changing the syntax, everything started to work as expected.
Should we avoid using arrow functions altogether when working with Fetch API?
Thanks!!!
3 Answers
Tim Graupe
6,902 PointsI had the same issue, the console gave the error code
Uncaught ReferenceError: can't access lexical declaration 'checkStatus' before initialization
The checkStatus function was set up as so
const checkStatus = (response) => {
if (response.ok) {
return Promise.resolve(response);
} else {
return Promise.reject(new Error(response.statusText));
}
}
However when it was changed to what it is below, it worked
const select = document.getElementById('breeds');
const card = document.querySelector('.card');
const form = document.querySelector('form');
// ------------------------------------------
// FETCH FUNCTIONS
// ------------------------------------------
function fetchData(url) {
return fetch(url)
.then(checkStatus)
.then(res => res.json())
.catch(error => console.log('Error found.', error))
}
Promise.all([
fetchData('https://dog.ceo/api/breeds/list'),
fetchData('https://dog.ceo/api/breeds/image/random')
])
.then(data => {
const breedList = data[0].message;
const randomImage = data[1].message;
generateOptions(breedList);
generateImage(randomImage);
})
// ------------------------------------------
// HELPER FUNCTIONS
// ------------------------------------------
function checkStatus(response) {
if (response.ok) {
return Promise.resolve(response);
} else {
return Promise.reject(new Error(response.statusText));
}
}
const generateOptions = (data) => {
const options = data.map(item => `
<option value='${item}'> ${item} </option>
`).join('');
select.innerHTML = options
}
const generateImage = (data) => {
let html =`
<img src='${data}' alt>
<p>Click to view images of ${select.value}s</p>
`;
card.innerHTML = html;
}
const fetchBreedImage = () => {
const breed = select.value;
const img = card.querySelector('img');
const p = card.querySelector('p');
fetchData(`https://dog.ceo/api/breed/${breed}/images/random`)
.then(data => {
img.src = data.message;
img.alt = breed;
p.textContent = `Click to view more ${breed}`
})
}
// ------------------------------------------
// EVENT LISTENERS
// ------------------------------------------
select.addEventListener('change', fetchBreedImage);
card.addEventListener('click', fetchBreedImage);
// ------------------------------------------
// POST DATA
// ------------------------------------------
Brandon White
Full Stack JavaScript Techdegree Graduate 35,771 PointsPiggybacking off of Jonathan Grieve, you should be fine using arrow functions with fetch. Unless I’m trying to make sure my functions are hoisted or I need this to be bound to the function, I almost exclusively use arrow functions (which includes when I’m making fetch requests).
Any chance you could share all of your code?
Brandon White
Full Stack JavaScript Techdegree Graduate 35,771 PointsFor those that don’t know what hoisted means, (in the context of this question) it essentially means that functions declared with the function keyword can be called from anywhere in that file. A function expression using const, let, or var is not hoisted. This means that the function can’t be called until after its expression appears in the code. So if you create a function const newFunction = () => {/* do something */}
on line 38, then you won’t be able to invoke the newFunction function before line 38. However, if you declare the same function using the function keyword (on line 38) you could call it from anywhere in that file (for instance, you could call it on line 2).
I don’t know that this was the original poster’s issue, but I suspect that it could have been. And seeing that it worked after changing the function expression to a function declaration gave the impression that the arrow function didn’t work.
Jonathan Grieve
Treehouse Moderator 91,253 PointsI'm not sure why this should be the case, to tell you the truth. The only difference I can see is the function definition syntax rather than what's inside it. I haven't seen anything online after a big search that confirms your question so for ow I would simply stick with what's working for you! :-)