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iOS Swift Functions and Optionals Optionals Optional Chaining

Why can't we say if var = //optional unwrapping We can only use if let. Thank you.

I'm curious to know why it has to be a constant declaration and not a variable when safely unwrapping optionals.

in previous video Amit says you can also use variable so we don't have to use constant , you can try it (i have tried it on optional example, it works ) . And also it bound to your function type.

I see now, thank you.

1 Answer

Just reposting the solution above so the answer shows up as answered:

"in previous video Amit says you can also use variable so we don't have to use constant , you can try it (i have tried it on optional example, it works ) . And also it bound to your function type."