Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript Node.js Basics Handling Errors in Node Handle Status Code Errors

Samuel Kleos
seal-mask
.a{fill-rule:evenodd;}techdegree
Samuel Kleos
Front End Web Development Techdegree Student 13,728 Points
Posted by Samuel Kleos
.a{fill-rule:evenodd;}techdegree
Samuel Kleos
Front End Web Development Techdegree Student 13,728 Points

Why create a new Error object just to print a statusCode error?

Why do you need to do this: 

statusCodeError = new Error(http.STATUS_CODES[response.statusCode])
printError(statusCodeError);

If you can just do this: 

console.print(http.STATUS_CODES[response.statusCode]);

1 Answer

Steven Parker
Steven Parker
231,275 Points
Steven Parker
Steven Parker
231,275 Points

The lesson begins with the creation of the "printError" method, and then all errors in processing are converted to make use of it. This is consistent with the "separation of concerns" design principle.

Your specific optimization does save a line of code, but it relies on knowledge of the internals of "printError". Should that be changed in the future (by a developer unaware of the dependency), this particular condition will no longer be handled consistently with the others.