Andrew, thanks for your help! About those quotation marks, though-- I'm still confused. I know it doesn't matter if you choose to use single or double quotes throughout your code. But isn't it taboo to use double quotes <strong>inside</strong> of double quotes (or single, inside of single, for that matter)? In this, for example:

$("#newColor").css( "background-color", "rgb("+ r +","+ g +","+ b +")" );

...see how he surrounded the "r, g & b" with double quotes, and then he used double quotes immediately after to encompass the "rgb()"? Maybe it was just a glitch in my browser, but when I tried the "correct" way of using single & double quotes, it wouldn't work. (I know it shouldn't matter if you use single quotes inside of doubles, or doubles inside of singles. But why do we have to "break the rule" and use the same type of quotation marks, in this case?)

You are correct in saying you should not use double quotes inside double quotes, but that isn't what Andrew is doing here. In the above code, Andrew is piecing together 6 different thing to make one string. I'll try to illustrate with some code:

var rgbOpen = "rgb(";
var rgbClose = ")";
var comma    = ",";
var r = "230";
var g = "24";
var b = "187"

//this is what the JS interpreter reads from the JS file
console.log( rgbOpen + r + comma + g + comma + b + rgbClose):
//this will print out "rgb(230,24,187)" in the console log

//this it what the JS interpreter translates the variables to
console.log(  "rgb(" + "230" + "," + "24" + "," + "187" + ")" );
//this will print out "rgb(230,24,187)" in the console log

//this is the final translation before logging the info to the console
console.log(  "rgb(230,24,187)" );
//this will print out "rgb(230,24,187)" in the console log

In the above code I should the 6 different part of the string that Andrew is putting together (I took the liberty of replacing the dynamic r, g, and b values with static ones). I hope this helps to clear things up for you.

Ah I see... It's like one of those optical illusions, lol. I get it now. Thanks so much for your patience in explaining it to me!

You have to concatenate the r, g, and b into the string because they are variables. In JS you can't directly input variables into a string without concatenating them because the interpreter has no way of telling the difference between a variable name and a word inside the string. This is because JS doesn't have a special character for variables. You have to use "var" to declare a variable, but not to use the variable. For example:

var name = "Andrew";

console.log("Hello, my name is " + name);
// prints "Hello, my name is Andrew" in the console.

This code works because the JS interpreter knows that outside of single or double quotes the word "name" actually means "Andrew". If this wasn't the case then above code would product "Hello, my Andrew is Andrew", since the word "name" inside "Hello, my name is" would also be replace with "Andrew".