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JavaScript

Steven Vallarsa
Steven Vallarsa
10,842 Points

Why did this solution work to the first filter/map problem in this video?

I tried many ways to solve the first filter/map coding challenge in the video, and accidentally stumbled upon a way that generates the correct result, but is different from the way Joel showed as the solution:

const userNames = ['Samir', 'Angela', 'Beatrice', 'Shaniqua', 'Marvin', 'Sean'];
    // Result: [{name: 'Samir'}, {name: 'Shaniqua'}, {name:'Sean'}];

const users = userNames
    .filter(name => name[0] === "S")
    .map(name => {
      return {name}  
    });

console.log(users);

Why is it that just using {name} allows that variable to be the key in the array of objects?

1 Answer

Steven Parker
Steven Parker
229,644 Points

When you write an object literal, giving only a variable name creates an attribute with the same name as the variable, and gives it the value of the variable.

so if name = "Dave", then { name } is the same as { name: "Dave" }.