Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Daniel Lee
Courses Plus Student 272 PointsWhy does an NSInteger variable have to typecasted to type long?
int main(int argc, const char * argv[]) {
@autoreleasepool {
NSNumber *myNumber, *intNumber;
NSInteger myInt;
myNumber = @1804809223;
myInt = (int) [myNumber integerValue];
NSLog(@"%i", myInt); <====
}
return 0;
}
The above gets an error as indicated by the arrow.
The correct NSLog message is actually NSLog(@"%lg", (long) myInt); Why do I have to convert the integer value of myInt to long if I want the value to display?
1 Answer
Amit Bijlani
Treehouse Guest TeacherIn a 64-bit environment by default an NSInteger is defined as a long.