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iOS

Why does an NSInteger variable have to typecasted to type long?

int main(int argc, const char * argv[]) {

@autoreleasepool {
    NSNumber *myNumber, *intNumber;

    NSInteger myInt;

    myNumber = @1804809223;
    myInt = (int) [myNumber integerValue];
    NSLog(@"%i",  myInt);  <==== 

}
return 0;

}

The above gets an error as indicated by the arrow.

The correct NSLog message is actually NSLog(@"%lg", (long) myInt); Why do I have to convert the integer value of myInt to long if I want the value to display?

1 Answer

Amit Bijlani
STAFF
Amit Bijlani
Treehouse Guest Teacher

In a 64-bit environment by default an NSInteger is defined as a long.