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JavaScript JavaScript Loops Working with 'for' Loops The Refactor Challenge – Duplicate Code

Posted by Casey Beaver
Casey Beaver
5,619 Points

Why does 'const' work to define this function, but 'function' wont?

Can someone explain why one of these is successful and the other isn't:

const getRandNum = () => Math.floor(Math.random() * 256);

function getRandNum() {Math.floor(Math.random() * 256);}

1 Answer

Mark Tripney
Mark Tripney
8,666 Points
Mark Tripney
Mark Tripney
8,666 Points

Remember that an arrow function has an implicit return — so, the arrow function's actually returning the evaluation of Math.floor(Math.random() * 256. Your function declaration has no return statement, so nothing's 'coming out of' that function.