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Python

Posted by Huijuan Pei
Huijuan Pei
1,537 Points

Why does it appear as syntax error ?

Why does it appear as syntax error when I try to run the following code?

try: a=int(input("Give me a number: ") except ValueError: print("This is not a number!") else: print('Hi'*a)

2 Answers

Dylan Rainwater
Dylan Rainwater
15,537 Points
Dylan Rainwater
Dylan Rainwater
15,537 Points

Hi Huijuan,

It appears that you are missing a second closing parenthesis around your input. It should be:

try: 
    a = int(input("Give me a number: ")) 
except ValueError: 
    print("This is not a number!") 
else: 
    print('Hi'*a)
Huijuan Pei
Huijuan Pei
1,537 Points
Huijuan Pei
Huijuan Pei
1,537 Points

Thanks Dylan. I looked at it for 30 minutes, couldn't spot the missing parenthesis. Guess I need a pair of glass for better coding :)

Dylan Rainwater
Dylan Rainwater
15,537 Points

No problem! It's always easy to miss a parenthesis here or there.