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JavaScript JavaScript Loops Working with 'for' Loops The Refactor Challenge – One Solution

Posted by dave li
dave li
723 Points

Why does my color stay the same throughout the loop ?

let html = ''; let red = Math.floor(Math.random() * 256); let green = Math.floor(Math.random() * 256); let blue = Math.floor(Math.random() * 256); let randomRGB = rgb( ${red}, ${green}, ${blue});

console.log(red) console.log(green) console.log(blue)

for(let i = 0; i <= 10; i++){

html += <div style="background-color: ${randomRGB}">${i}</div>; }

document.querySelector('main').innerHTML = html;

How will I refactor this code so that I get a random RGB for each loop ?

1 Answer

Joseph Yhu
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Joseph Yhu
PHP Development Techdegree Graduate 48,637 Points
Joseph Yhu
.a{fill-rule:evenodd;}techdegree seal-36
Joseph Yhu
PHP Development Techdegree Graduate 48,637 Points

It's because the code that generates random colors is outside the for loop, which means it will generate only a single random color. You have to put the code inside, like this:

for (let i = 0; i <= 10; i++) {
    red = Math.floor(Math.random() * 256);
    green = Math.floor(Math.random() * 256);
    blue = Math.floor(Math.random() * 256);
    randomRGB = `rgb( ${red}, ${green}, ${blue} )`;
    html += `<div style="background-color: ${randomRGB}">${i}</div>`;
}