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Python Python Basics All Together Now Branch and Loop

Posted by Sabeen Azhar
Sabeen Azhar
440 Points

why does my if else statement not work?

why is 

confirm = input("do you want to proced? Y/N    ")

in a loop even if one these perameters are met?

if confirm == "y":
    print("SOLD!")
    tickets_remaining -= number_of_tickets 
elif confirm == "n":
    sys.exit("thanks anyways {}!".format(name))

thanks in advance!

import sys

TICKET_PRICE = 10

tickets_remaining = 100

print("there are {} tickets left".format(tickets_remaining))

name = input("what is your name?    ")

number_of_tickets = int(input("how much tickets would you like, {}?    ".format(name)))

amount_due = number_of_tickets * 10
print("that would be ${}, {}.".format(amount_due, name))

print("are you sure you want to go through with this?    ")

confirm = input("do you want to proced? Y/N    ")
while confirm.lower != ("y", "n"):
    print("whoops! try again!")
    confirm = input("do you want to proced? Y/N    ")

if confirm == "y":
    print("SOLD!")
    tickets_remaining -= number_of_tickets 
elif confirm == "n":
    sys.exit("thanks anyways {}!".format(name))
    ```

2 Answers

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,441 Points

Hey Sabeen Azhar, there a a few problems with your while loop conditional

  • confirm.lower is a bound method. Without specifying the () parens to call the function, this is a reference to the executable itself.
  • comparing to a tuple ("y", "n") will only match another tuple of the same values.

You can use the in operator to see if something is "in" a container of values, such as a tuple:

while confirm.lower() not in ("y", "n"):

Post back if you need more help. Good luck!!

Sabeen Azhar
Sabeen Azhar
440 Points
Sabeen Azhar
Sabeen Azhar
440 Points

Thank you for the answer Chris Freeman, it worked perfectly!