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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Tim Blacquier
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Tim Blacquier
Full Stack JavaScript Techdegree Graduate 20,961 Points

Why does this code work in workspaces but not in the code challenge??

I have tested this code in workspaces and it works perfectly. Can not figure out why this will not pass the challenge.

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(str):
    words = str.split(" ")
    word_count_dict = {}
    for word in words:
        try:
            word_count_dict[word.lower()] += 1
        except KeyError:
            word_count_dict[word.lower()] = 1
    return word_count_dict

1 Answer

Brennan White
Brennan White
11,646 Points

You are splitting on " ", which is technically just a space. You are not splitting on whitespace. The difference doesnt change the output here, but this is what it is looking for:

def word_count(str):
    words = str.split()
    word_count_dict = {}
    for word in words:
        try:
            word_count_dict[word.lower()] += 1
        except KeyError:
            word_count_dict[word.lower()] = 1
    return word_count_dict