Python Python Collections (2016, retired 2019) Dictionaries Word Count

Tim Blacquier
Tim Blacquier
Full Stack JavaScript Techdegree Graduate 20,158 Points

Why does this code work in workspaces but not in the code challenge??

I have tested this code in workspaces and it works perfectly. Can not figure out why this will not pass the challenge.

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(str):
    words = str.split(" ")
    word_count_dict = {}
    for word in words:
        try:
            word_count_dict[word.lower()] += 1
        except KeyError:
            word_count_dict[word.lower()] = 1
    return word_count_dict

1 Answer

Brennan White
Brennan White
9,502 Points

You are splitting on " ", which is technically just a space. You are not splitting on whitespace. The difference doesnt change the output here, but this is what it is looking for:

def word_count(str):
    words = str.split()
    word_count_dict = {}
    for word in words:
        try:
            word_count_dict[word.lower()] += 1
        except KeyError:
            word_count_dict[word.lower()] = 1
    return word_count_dict
Tim Blacquier
Tim Blacquier
Full Stack JavaScript Techdegree Graduate 20,158 Points

That works! In JavaScript you have to specify the space, that's what messed me up. Thank you!