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Python Python Collections (2016, retired 2019) Tuples Combo

Kevin Myers
Kevin Myers
7,604 Points

Why does this return a TyperError: 'int'? It works on workspaces but on the challenge I get an error

def combo(args, args_2): my_list = [] a = 0 for arg in args:

    for blarg in args_2[a]:
        my_tuple = (arg, blarg)
        my_list.append(my_tuple)
        a += 1
return(my_list)
combo.py
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]

def combo(args, args_2):
    my_list = []
    a = 0
    for arg in args:

        for blarg in args_2[a]:
            my_tuple = (arg, blarg)
            my_list.append(my_tuple)
            a += 1
    return(my_list)   

1 Answer

Steven Parker
Steven Parker
229,921 Points

I'm sure the challenge tests your code more thoroughly than just running the example through it. And it should not matter what kind of iterables the objects are, or in which order they are given.

Try testing your code using this to see the issue:

combo('abc', [1, 2, 3])

Hint: you probably don't need 2 loops.