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JavaScript JavaScript Loops Working with 'for' Loops The Refactor Challenge – Duplicate Code

Why Does This Work? Refractor Challenge Pt 2

After going through the full refraction process in the challenge, I am left confused only by the last update. Here is the code:

let html = '';
const randomValue = () => Math.floor(Math.random() * 256);

function randomRGB(value) {
  const color = `rgb( ${value()}, ${value()}, ${value()} )`;
  return color;
}

for ( let i = 1; i <= 100; i++ ) {
  html += `<div style="background-color: ${randomRGB(randomValue)}">${i}</div>`;
}

document.querySelector('main').innerHTML = html;

The part I don't understand is:

function randomRGB(value) {
  const color = `rgb( ${value()}, ${value()}, ${value()} )`;
  return color;
}

I understand that 'value' is a parameter, but I don't understand where the argument is being passed through it, or specifically, where the value of 'value' is coming from, in the 'color' const.

This felt tricky to explain. If you would like me to clarify please let me know!

1 Answer

Jason Anders
MOD
Jason Anders
Treehouse Moderator 145,547 Points

Hi Chelsea Cheevers

The argument being passed to the function is coming from the result of the randomValue variable. I think that is just because the names of the variable and the function are similar that it is a bit tricky to track quickly.

In the loop, the randomRGB function is being called and the value from the randomValue constant is being passed in. Guil goes through this part of the code starting at 4:41 in the video

I hope that helps.

:) :dizzy: