###### Parvez Noor

Pro Student 11,885 Points# Why does y = 5?

The question asked what y =. I chose 5 because the parameters in the function sum_two_numbers when setting the y variable are 2,3.

Does this mean that because the y variable is called later than when the x variable is defined, that within the function, x becomes 2 and y becomes 3, and therefore y becomes the return of z (which is 5) because y = the output of the function?

What confuses me about this, though, is doesn't mean that mean in the function y=5 and x=1? wouldn't that make it 6??

It's a little confusing!

$x = 1;

function sum_two_numbers($x,$y) { $z = $x + $y; return $z; }

$y = sum_two_numbers(2,3); echo $y;

## 1 Answer

###### Steven Parker

167,906 PointsThe important thing to remember for this question is the rules of __variable scope__. The $x and $y inside the function are totally different from the ones outside the function.

Inside the function, you were right the first time in that $x is 2 and $y is 3; because they were passed as arguments. And arguments "shadow" (take precedence over) any globals of the same name.

But outside the function, $x is still 1 and $y gets assigned to return value from the function. And those two are never added together.