# Why doesn't list.remove() removes all the elements after using a for in loop, but using loop in for list.copy() does?

```#code for review - aim to remove all the elements from the list
l = [1,2,3,4,5,6]

#removed one element
l.remove(2)
#looping through list and removing element
for num in l:
l.remove(num)
#expected an empty list but instead got two items that too not the last two
print (l)

#if I use l.copy() in the loop then it works
for num in l.copy():
l.remove(num)
#got an empty list
print(l)
```

MOD

Modifying the loop iterable shifts the items relative to their indexes:

```#code for review - aim to remove all the elements from the list
l = [1,2,3,4,5,6]

#removed one element
l.remove(2)
#looping through list and removing element
for idx, num in enumerate(l):
l.remove(num)
print('loop 1:', l, idx, num)
#expected an empty list but instead got two items that too not the last two
print ('result 1:', l)

l = [1,2,3,4,5,6]

#if I use l.copy() in the loop then it works
for idx, num in enumerate(l.copy()):
l.remove(num)
print('loop 2:', l, idx, num)
#got an empty list
print('result 2:', l)
```

Produces

```loop 1: [3, 4, 5, 6] 0 1
loop 1: [3, 5, 6] 1 4
loop 1: [3, 5] 2 6
result 1: [3, 5]
loop 2: [2, 3, 4, 5, 6] 0 1
loop 2: [3, 4, 5, 6] 1 2
loop 2: [4, 5, 6] 2 3
loop 2: [5, 6] 3 4
loop 2: [6] 4 5
loop 2: [] 5 6
result 2: []
```

After half an hour of this, I understood it.

Basically, how the for loop is working is first taking the index, say '0', then assigning it to the variable we chose. e.g., in Chris's awesome reply above, python first takes idx as 0, then assigns the value at 0th position to num, which is '1' and removes it. The second time, idx is set to 1, and assigns the second element in the list (second will be like 0, then 1). and the second position of the modified list is not '3' anymore. It is '4', which removes it. Computers can be smart, but sometimes! :D

Chris's example above is great and helped me understand this concept and also I learnt the enumerate() function! Thanks a lot Chris! :) ta