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simon bao
5,522 PointsWhy doesn't this work? If i insert print(count) into the code it shows 2, which is the correct number.
def members():
my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
count = 0
for word in my_dict:
if word in my_list:
count += 1
return count
# You can check for dictionary membership using the
# "key in dict" syntax from lists.
### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2
def members():
my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
count = 0
for word in my_dict:
if word in my_list:
count += 1
return count
1 Answer
Chris Jones
Java Web Development Techdegree Graduate 23,933 PointsHey simon,
You're very close. Because you're writing a function, the dictionary and list will be passed into the function. So, you don't need to define those as my_dict and my_list. Try deleting those two variables and you should pass the code challenge.
def members(d, l):
count = 0
for word in d:
if word in l:
count += 1
return count
Let me know if you have any questions or any more issues.