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Ruby Ruby Basics (Retired) Ruby Methods Method Returns: Part 2

Posted by Carlo De Gregorio
Carlo De Gregorio
411 Points

why doesn't this work? It works in IRB

def mod(a, b) c = (a % b) return puts "The remainder of #{a} divided by #{b} is #{c}."
end

method.rb 
def mod(a, b)
  c = (a % b)
  return puts "The remainder of #{a} divided by #{b} is #{c}."
end

1 Answer

Kourosh Raeen
Kourosh Raeen
23,732 Points
Kourosh Raeen
Kourosh Raeen
23,732 Points

Don't use puts. Just return the string:

def mod(a, b)
  #write your code here
  c = (a % b)
  return "The remainder of #{a} divided by #{b} is #{c}."
end