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iOS

Posted by Enrique Bernal
Enrique Bernal
3,584 Points

Why I am receiving this alert?

writing the same code as Douglass, I am receiving this alert, the video is not showing the alert and results are not the same...

char letters[] = {'a', 'b', 'c'};
    int w= 0;
    while (w < 3) {
        printf("letter %d is c%\n", w, letters[w]);
        ++w;

The line of code: printf("letter %d is c%\n", w, letters[w]);

XCODE says: Invalid conversion specifier '

3 Answers

Andres Oliva
Andres Oliva
7,810 Points

You have to write "%c" not "c%" :)

Jeremy Hayden
Jeremy Hayden
1,740 Points

Upvoted ya! Good eye!

Andres Oliva
Andres Oliva
7,810 Points

Thanks!

Jeremy Hayden
Jeremy Hayden
1,740 Points
Jeremy Hayden
Jeremy Hayden
1,740 Points

Something doesn't look right. What lesson are you on?

Enrique Bernal
Enrique Bernal
3,584 Points
Enrique Bernal
Enrique Bernal
3,584 Points

Thanks a lot @Andres Oliva.

Jeremy Hayden I am doing the Objective-c course. Just starting the track. Thanks