Here's what I came up with

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

# Your code goes below here
the_list.pop(3)
the_list.insert(0, 1)
the_list.remove([1, 2, 3])
del the_list[1]
del the_list[3]

the_list.extend(range(4,21))

Quite a mental approach I must say, but it works!

It'll .extend() the list with the range() just fine. The problem is the contents of your the_list before and after the .extend(). It should be 1-20 with each number only appearing once...what do you have?

Ah, get it now!

Suggestion: Rephrase the text to "Make the list contain ONLY the numbers 1 to 20 using extend()" That would make it much clearer that it's not just a matter of making the list contain the numbers (which extend(1, 21) does), but of making sure 1-20 is all it contains.

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
the_list.insert(0, the_list.pop(3))  # the_list is now [1, "a", 2, 3, False, [1, 2, 3]]
the_list.remove('a')
the_list.remove(False)
the_list.remove([1, 2, 3])
the_list.extend(range(4,21))

these are my codes why its not working? i had already 1 2 3 in my list so i just add the rest

I was getting an error here as well

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

# Your code goes below here

the_list.insert(0, the_list.pop(3))

list=[5, 4, 1]

for numbers in list:
  del the_list[numbers]

the_list.extend(range(4,21))
print(the_list)

Error: Traceback (most recent call last): File "4fd7aca7-edd9-4f26-bb1e-8f7ba011333e.py", line 105, in """) File "", line 2, in TypeError: 'list' object is not callable

I tested the script in workspace and it works fine for me.

You can just reset the list right before adding the numbers.

the_list = []
the_list.extend(range(1, 21))

''' x = the_list.pop(3) the_list.insert(0,x) del the_list[1] del the_list[3] del the_list[3] '''

Will need to work that out - but the code passed the prior assignment so I didn't think much about that :-)

This doesn't work either - so I'm thinking it's a bug?

x = the_list.pop(3)

the_list.insert(0,x)

the_list.remove("a")

the_list.remove(False)

the_list.remove([1, 2, 3])

the_list.extend(range(1,21))

MUZ140330 Simbarashe Chibgwe is correct. it worked for me when I placed my code where it say's # Your code goes below here:

How do you post your code so it looks like that? I tried the ''' method from the markdown cheatsheet, but it doesn't work. Any tips? My code looks exactly like you guys' but it's saying Task 1 is no longer passing.

Here's my code:

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

# Your code goes below here
the_list.insert(0, the_list.pop(3))
the_list.remove("a")
the_list.remove(False)
the_list.remove([1, 2, 3])
the_list.extend(range(4:21))

Is there no way to remove all items in one step? E.g. the_list.remove("a", False, [1, 2 ,3])??

Hi Guys,

I actually figured this out by creating another list. There are better ways to do this, but it was get you past the test.

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
the_list2 = [4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]
# Your code goes below here

p = the_list.pop(3)

s = the_list.insert(0, p)

the_list.remove("a")
the_list.remove(False)
the_list.remove([1, 2, 3])

the_list.extend(the_list2)

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
index = the_list.pop(3)
the_list.insert(0, index)
the_list.remove("a")
del the_list[3]
del the_list[3]
print (the_list)
#checks and loops until the last number in the list reaches 20 
while the_list[-1] != 20:
    #add 1 to the last number in the list every time it loops and append it to the_list
    the_list.append(the_list[-1] + 1)
    print (the_list)

if anyone needs help this is the solution, but be sure to read through and understand

the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

Your code goes below here

the_list.insert(0, the_list.pop(3))

the_list.remove("a") the_list.remove(False) the_list.remove([1,2,3])

the_list.extend(range(3, 21))