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hannah4
17,400 PointsWhy is 'i' worth 10 outside the loop ?
I know it's probably a very silly question but I struggle to understand, not the scope, the concept is clear, but why would the last console.log(i) prints 10 when it's previously left with a worth of 9 and nothing tells it to add anything further in this example (it's outside the loop already...), can someone please tell me why that is ? Thanks :)
var i; // i is declared in the global scope
for ( i = 0; i < 10; i++ ) { console.log(i); // logs the numbers 0 to 9 }
console.log(i); // 10
2 Answers
jhon white
20,006 PointsBecause of the last alliteration of the loop (i) equal (9), but nine is less than (10) , so it goes to the loop body and update (i) to became (10).
hannah4
17,400 PointsOk thanks a lot ! Silly I know, but it's been bugging me :)
jhon white
20,006 PointsIt is okey, always ask about anything you don't fully understand because that will makes you a better developer.
Mark Casavantes
10,619 PointsMark Casavantes
10,619 PointsGood Morning Outlandos,
In your for loop the numbers progress from 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. 9<10 is true. When the program reaches i++ i is incremented one more time so the 9 becomes a 10. The next time the program loops 10<10 and the program stops. i remains equal to 10.