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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Imran Hossain
Imran Hossain
5,353 Points

Why is my code not working

Can anyone tell me why my code isnt being accepted ?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(sentence):
    wordList = sentence.split(" ")

    dic = {}

    for i in wordList:
        dic[i.lower()] = sentence.count(i)
    return dic

2 Answers

Donatas Ramanauskas
Donatas Ramanauskas
28,538 Points
Donatas Ramanauskas
Donatas Ramanauskas
28,538 Points

because this line of code counts, how many times in sentence word appears:

dic[i.lower()] = sentence.count(i)

so for example if you've a sentence:

"i do not like it Sam i Am"

the dic["i"] would be 4, should be 2.

Dan Martin
Dan Martin
2,385 Points
Dan Martin
Dan Martin
2,385 Points

Hello. I was having this problem too. It turns out when you .split(" ") you are only splitting the spaces between words, whereas .split() splits at all white spaces such as tabbing. This is what I saw in a post on another page.