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Raaghav Chaudhry
464 Pointswhy is my code not working?
My code looks similar but it is not working. Here is the screenshot.
import UIKit
var number = 10
if number % 3 == 0 {
println("Fizz")
} else if number % 5 == 0 {
println("Buzz")
}
else if number % 3 == 0 && number % 5 {
println("FizzBuzz")
}
else{ println("number")
}
4 Answers
thomascawthorn
22,986 PointsPerhaps you need to add == 0 on this rule?
number % 3 == 0 && number % 5 == 0 {
Loubna Aggoun
4,052 PointsWhat does the error say ?
Your code will not work because this condition :
if number % 3 == 0 && number % 5 == 0 {
println("FizzBuzz")
}
should be the first one.
Indeed, if you test with number 6, it will go through the first condition and return Fizz, if you test with number 10 it will go through the second condition and return Buzz. However, if you test with 15 which is a multiple of both 3 and 5, you will only go through the first condition as 15 can be divided by 3. As a consequence, you will never reach the 3rd condition and it will never print "FizzBuzz".
Raaghav Chaudhry
464 Pointsthank you vey much
Raaghav Chaudhry
464 Pointsthank you vey much
Raaghav Chaudhry
464 PointsRaaghav Chaudhry
464 PointsYes, I figured that out but I'm still getting an error.
import UIKit var number = 10
if number % 3 == 0 { println("Fizz") } else if number % 5 == 0 { println("Buzz") } else if number % 3 == 0 && number % 5 ==0 { println("FizzBuzz") } else{ println("number") }