Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

JavaScript AJAX Basics (retiring) AJAX and APIs Call the jQuery $.getJSON method

Leo Marco Corpuz
Leo Marco Corpuz
18,975 Points

Why is my $.getJSON not working?

For the code challenge, the url and data are stored in variables.I stored the callback function in a variable also. Now I just put these variables as arguments to $.getJSON() and I get an error saying I need to use the $.getJSON() storing the arguments in proper order. I'm lost.

weather.js
$(document).ready(function() {

  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
  var data = {
    q : "Portland,OR",
    units : "metric"
  };
  var response= function showWeather(weatherReport) {
    $('#temperature').text(weatherReport.main.temp);
  }

  $.getJSON(weatherAPI, data, response);

});
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>What's the Weather Like?</title>
  <script src="jquery.js"></script>
  <script src="weather.js"></script>
</head>
<body>
  <div id="main">
    <h1>Current temperature: <span id="temperature"></span>&deg;</h1>
  </div>
</body>
</html>

2 Answers

Try this:

$(document).ready(function() {

  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';

  var data = {
    q : "Portland,OR",
    units : "metric"
  };

  function showWeather(weatherReport) {
    $('#temperature').text(weatherReport.main.temp);
  }

  $.getJSON(weatherAPI, data, showWeather);

});

The response will be invalid because openweathermap requires an API key now. But it will get you through the quiz.

hamdi taboubi
hamdi taboubi
3,627 Points

remove $.getJSON(weatherAPI, data, response);