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Vineet Kapoor
3,955 PointsWhy is the following code wrong for challenge task 1 of 1 of Ruby Loops?
Using the loop construct, add the current value of number to the numbers array. Inside of the loop, add 1 to the number variable. If the numbers array has more than 3 items, use the break keyword to exit the loop.
numbers = [] number = 0
numbers << number loop do if numbers.length > 3 break else number += 1 end numbers << number end
numbers = []
number = 0
numbers << number
loop do
if numbers.length > 3
break
else
number += 1
end
numbers << number
end
# write your loop here
4 Answers
Erika Wedenoja
14,947 PointsI think your code is correct but the challenge question is worded incorrectly. If you break out of the loop when the numbers array has more than three items, you get a hint that the numbers array does not contain three items. However, using your code and setting the break
if numbers.length > 2
passes the challenge. So it seems the question is asking you to create a 4 item array and the grader is checking for a 3 item array.
Erika Wedenoja
14,947 PointsDavid,
Thanks, that's a good idea. I've sent this question to the Treehouse Support Team for review.
Erika Wedenoja
14,947 PointsJason Seifer,
Would you please explain this seemingly simple Ruby Loops Challenge. There is ongoing confusion about the correct answer. I emailed the Treehouse Support team but was directed back to the Community Forum.
This is the issue: The challenge question asks you to exit a loop if the numbers array has more than 3 items. However, you are only able to pass this challenge if you exit the loop as soon as the numbers array has more than 2 items. To me and some other students on the forum, these are two different things. What are we missing?
Eric Trego
15,308 Pointsyou all are using way more code then is needed
loop do
number += 1
numbers.push(number)
if numbers.length > 2
break
end
end
this is the code for the loop.
hope this helps and happy coding
David Clausen
11,403 PointsEric, count =/= index. A array with an three items [1,2,3] had a length of 3, its index would be 0,1,2.
The question is asking for number of items, not index. It's askng to stop after having a total of More than 3 objects. If you have more than 3 you will have to stop at four.
If you inspect you array you will see you break at exactly 3.
Is having three items more than 3?
This isn't about more work vs not...this is simply wrong and its confusing people. You now have index and count/length mixed up. This is quite annoying and its vital to understand the difference of the two.
Length/count is the quantity, I'd you have zero items you have 0 length. Index is the position in a collection items are stored, this starts at zero.
A array that has four items you will need to use index of 3 to access the last item and 0 to access the first and -1 to access the last element.
Hope this clears up what the crux of the issue is.
Vineet Kapoor
3,955 PointsVineet Kapoor
3,955 PointsThanks Erika!
David Clausen
11,403 PointsDavid Clausen
11,403 PointsYes! I've actually brought this up and even a moderator here couldn't comprehend the question and the evaluation are checking for two different things. I submitted a ticket though. This is going to confuse a lot of new programmers with the wording and check being different. I'd highly recommend submitting a ticket Erika since you understand the issue to so we can hopefully get it resolved for others.
Thanks!