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Python Python Basics All Together Now Handle Exceptions

Posted by Faraz Jahangiri
Faraz Jahangiri
1,028 Points

Why is there a type error for the ">" sign?

TICKET_PRICE = 23.99

tickets_remaining = 100

while tickets_remaining >= 1: user_name = input("Please enter your name: ") print("There are {} tickets remaining.".format(tickets_remaining))

amount_purchased = input("How many tickets would you like {}? ".format(user_name))

try: if amount_purchased > tickets_remaining: raise ValueError("That is not possible, sorry") amount_purchased = int(amount_purchased) except ValueError: print("That is not a valid value, please enter a number") else:
total_cost = TICKET_PRICE * amount_purchased 

print("your total for this is £{}".format(total_cost))
proceed = input("Do you want to proceed with this sale, PLease enter yes or no: ")

if proceed == "yes":
  print("SOLD!!")
  tickets_remaining -= amount_purchased
elif proceed == "no":
  print("Ok, Thank you anyway!")
else:
  print("That is not a valid answer")

print("We are so sorry but we are all out of tickets")

The problem is, I am trying to raise an exception Error but the code stops running after the if statement which says, "amount_purchased > tickets_remaining?

nakalkucing
nakalkucing
12,964 Points
nakalkucing
nakalkucing
12,964 Points

Hi Faraz Jahangiri! I'd like to help, but your code isn't in proper syntax. While I can correct the syntax in my workspace, I can't be sure that it's set up the same way as yours.

    ```python
    def proper_syntax():
        print("""You can achieve proper syntax 
                 by typing three back-tics and the name of your coding language.
                 End with three more back-tics.  As seen around this block of code.""")
    ```

Hope this helps! :)

1 Answer

Jennifer Nordell
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STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there, Faraz Jahangiri ! The problem here is that you cannot compare a string to an integer in this way. The input that the user gives will be of type string. And tickets_remaining is an integer. To compare them, you will first need to convert the user's input to an int.

On line 9 try this instead:

# convert the user's input to an integer for comparison
amount_purchased = int(input("How many tickets would you like {}? ".format(user_name)))

Hope this helps! :sparkles: