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Shavez MemonPython Development Techdegree Student 2,451 Points
Why is there an error?
I run this code and the error says 'Uh oh, 1 is odd but is_odd(1) returned False.' However, is_odd(1) is True in my code
def is_odd(parameter): if parameter%2!=0: print('True')
Patricia Hector42,901 Points
This code will be marked as correct for this challenge because it returns True for odd numbers:
def is_odd(parameter): if parameter % 2 != 0: return True
If you want to include also even numbers, just add:
def is_odd(parameter): if parameter % 2 != 0: return True else: return False
The last function read as follow:
- The is_odd(..) function receives a numeric parameter
- If that parameter is not even (<=> odd), the function will exit returning True
- Otherwise the function will exit returning False