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Start your free trialShavez Memon
Python Development Techdegree Student 2,452 PointsWhy is there an error?
I run this code and the error says 'Uh oh, 1 is odd but is_odd(1) returned False.' However, is_odd(1) is True in my code
def is_odd(parameter):
if parameter%2!=0:
print('True')
1 Answer
Patricia Hector
42,902 PointsThis code will be marked as correct for this challenge because it returns True for odd numbers:
def is_odd(parameter):
if parameter % 2 != 0:
return True
If you want to include also even numbers, just add:
def is_odd(parameter):
if parameter % 2 != 0:
return True
else:
return False
The last function read as follow:
- The is_odd(..) function receives a numeric parameter
- If that parameter is not even (<=> odd), the function will exit returning True
- Otherwise the function will exit returning False