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Java Java Basics Perfecting the Prototype String Equality

Posted by sara oren
sara oren
1,798 Points

Why is this causing a compile error?

if (firstExample === secondExample) { console.printf("first is equal to second"); System.exit(0); }

Equality.java 
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
if (firstExample === secondExample) {
    console.printf("first is equal to second");
    system.exit(0)
};
String thirdExample = "HELLO";

3 Answers

Rich Bagley
Rich Bagley
25,869 Points
Rich Bagley
Rich Bagley
25,869 Points

Hi Sara,

Try changing this line:

if (firstExample === secondExample) {

to:

if (firstExample.equals(secondExample)){

and remove this line:

   system.exit(0)

Hope that helps

-Rich

Lee Reynolds Jr.
Lee Reynolds Jr.
5,160 Points
Lee Reynolds Jr.
Lee Reynolds Jr.
5,160 Points

You could also just drop ff one of the equal signs. Instead of "===", "==" should work. Happy Coding.