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JavaScript JavaScript Basics (Retired) Storing and Tracking Information with Variables Using String Methods

Hariharan Ramesh
Hariharan Ramesh
7,403 Points

why is this code not working?

var id = "23188xtr"; var lastName = "Smith"; id.toUpperCase(); var userName=id+'#'+lastName.toUpperCase();

OUTPUT must be==23188XTR#SMITH

app.js
var id = "23188xtr";
var lastName = "Smith";
id.toUpperCase();
var userName=id+'#'+lastName.toUpperCase();
index.html
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="app.js"></script>
</body>
</html>

1 Answer

Roberto Alicata
PLUS
Roberto Alicata
Courses Plus Student 39,959 Points

You need to assign the uppercase version of the id to the userName variable in the first step:

var userName = id.toUpperCase();

then to complete the assignment you need to use the string concatenation (using the plus sign "+"):

var userName = id.toUpperCase() + "#" + lastName.toUpperCase();

N.B. in your code when you call the toUpperCase() method on the id variable you forgot to assign the result to the userName variable so you have lost it in the next assignement.