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JavaScript JavaScript and the DOM (Retiring) Getting a Handle on the DOM Selecting Multiple Elements

Tauan Flores
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.a{fill-rule:evenodd;}techdegree
Tauan Flores
Front End Web Development Techdegree Student 5,277 Points

Why is this incorrect? let listItems = document.querySelectorAll('#rainbow');

Why is this incorrect? let listItems = document.querySelectorAll('#rainbow');

index.html
<!DOCTYPE html>
<html>
  <head>
    <title>Rainbow!</title>
  </head>
  <body>
    <ul id="rainbow">
      <li>This should be red</li>
      <li>This should be orange</li>
      <li>This should be yellow</li>
      <li>This should be green</li>
      <li>This should be blue</li>
      <li>This should be indigo</li>
      <li>This should be violet</li>
    </ul>
    <script src="js/app.js"></script>
  </body>
</html>
js/app.js
let listItems = document.querySelectorAll('#rainbow');
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];

for(var i = 0; i < colors.length; i+=1) {
  listItems[i].style.color = colors[i];    
}

1 Answer

Spencer Bigum
Spencer Bigum
3,250 Points

you're only selecting the main UL element. You need to target the children of it.

let listItems = document.querySelectorAll('#rainbow')[0].children;

This is inappropriate because you use CSS selector when there is no CSS involved here and the course doesn't cover the .children tag so far.