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Java Java Basics Getting Started with Java Strings and Variables

Courses Plus Student 524 Points

Why is variable to be written after we use %s ?

String firstName = "Shaun";

console.printf("Hello my name is %s\n"firstName)

2 Answers

Grigorij Schleifer
Grigorij Schleifer
10,363 Points


the %s is a String formatter. It will be replaced by the variable (here your name). After you close the text ("some text with the %s formatter" there should be a comma and then the variable name. It is a convention of the printf method. This method takes a text first and then the variable name that replaces the %s String formatter.

Makes sense?

And I see two typos here:

console.printf("Hello my name is %s\n", firstName); // comma and semicolon added


S Nafees Hyder
S Nafees Hyder
649 Points

because %s may refer to format specifiers for variable interpolation in C standard and other libraries