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SHANTANU RANACourses Plus Student 524 Points
Why is variable to be written after we use %s ?
String firstName = "Shaun";
console.printf("Hello my name is %s\n"firstName)
Grigorij Schleifer10,365 Points
the %s is a String formatter. It will be replaced by the variable (here your name). After you close the text ("some text with the %s formatter" there should be a comma and then the variable name. It is a convention of the printf method. This method takes a text first and then the variable name that replaces the %s String formatter.
And I see two typos here:
console.printf("Hello my name is %s\n", firstName); // comma and semicolon added
S Nafees Hyder649 Points
because %s may refer to format specifiers for variable interpolation in C standard and other libraries