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Python Python Collections (2016, retired 2019) Lists Disemvowel

Kevin S
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.a{fill-rule:evenodd;}techdegree
Kevin S
Data Analysis Techdegree Student 15,862 Points
Posted by Kevin S
.a{fill-rule:evenodd;}techdegree
Kevin S
Data Analysis Techdegree Student 15,862 Points

Why isn't my code working here.

When i run the function, it takes out most of the vowels but seems to arbitrarily leave one in the string of characters. Can someone figure out why?

Thanks!

disemvowel.py 
def disemvowel(word):
    word = list(word)
    for letter in word:
        seached = letter.lower()
        if seached == 'a':
            word.remove(letter)
        elif seached == 'e':
            word.remove(letter)
        elif seached == 'i':
            word.remove(letter)
        elif seached == 'o':
            word.remove(letter)
        elif seached == 'u':
            word.remove(letter)
        else:
            continue
    return ''.join(word)

1 Answer

Alexander Davison
Alexander Davison
65,469 Points
Alexander Davison
Alexander Davison
65,469 Points

Strange things can happen when you modify the iterable you are looping on within the loop. Instead, try making a new variable which holds a string, and if the current letter is not a vowel, append the letter to the variable:

def disemvowel(word):
    new_word = ''
    for letter in word:
        if letter.lower() not in 'aeiou':
            new_word += letter
    return new_word

I hope this helps! :grin: :zap: ~Alex

EDITED