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Python Python Basics (2015) Shopping List App Break

Michael Dinnall
Michael Dinnall
6,730 Points
Posted by Michael Dinnall
Michael Dinnall
6,730 Points

why isnt my function working ? Needed: a break to exit the loop

def loopy(items): for item in items:
if item == 'STOP': break return item

breaks.py 
def loopy(items):
   for item in items:    
    if item == 'STOP':
      break

2 Answers

Alexandra Barnett
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Alexandra Barnett
Front End Web Development Techdegree Graduate 46,473 Points
Alexandra Barnett
.a{fill-rule:evenodd;}techdegree seal-36
Alexandra Barnett
Front End Web Development Techdegree Graduate 46,473 Points

Hi Michael! I see that you have returned the item if it's not a break? I think the challenge wants you to print the item like this:

def loopy(items):
    # Code goes here
    for item in items:
        if item == "STOP":
            break
        print(item)

Hope that helps! Let me know if you have any questions! :)

Michael Dinnall
Michael Dinnall
6,730 Points
Michael Dinnall
Michael Dinnall
6,730 Points

Hi Alexandra its still given me "Bummer! Didn't find the right items being printed." I also tried:

def loopy(items):
    for item in items:
        if item == "STOP":
            break
        print(item)
loopy(items)

I still got the same result

Michael Dinnall
Michael Dinnall
6,730 Points
Michael Dinnall
Michael Dinnall
6,730 Points

Actually, I just solved it. I was printing (item) not (items). Thanks for your suggestion it made me look into it a little more !