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JavaScript What are Closures?

Why isn't the counter variable reset every time the function is called?

He mentions that every time the outer function is called, a new private scope is created? What does he mean by this? Also, wouldn't the counter variable reset every time the function is called?

1 Answer

Steven Parker
Steven Parker
231,248 Points

What creating a new private scope means is that each "innerFunction" would have its own "someCount" variable. But while the "someCount" variable is in the scope of the inner function, it's not itself a part of the inner function, so it would not get reset when the inner function is called.