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iOS Swift Basics (retired) Control Flow Exercise: FizzBuzz Generator

Posted by Giulio Autelitano
Giulio Autelitano
554 Points

Why isn't this working?

var number = 15

var three = (number)%3

var five = (number)%5

if five == 0 && three == 3 { println("BuzzFizz") } else if five == 0 { println("Buzz") } else if three == 0 { println("Fizz") }

3 Answers

umerrathore
umerrathore
2,558 Points
umerrathore
umerrathore
2,558 Points

The problem is with this statement:

"if five == 0 && three == 3"

It should be:

"if five == 0 && three == 0"

as your variable three evaluates whether there is any remainder when dividing by the number 3. For the number 15, there would be no remainder for dividing by 5 or by 3, so you 'three' variable would be 0. As such, the way you have written it, the first If condition is never met when number = 15.

I hope this helps!

Srinivasan Senthil
Srinivasan Senthil
2,266 Points
Srinivasan Senthil
Srinivasan Senthil
2,266 Points

hahaha.. this was a good one... people have explained the answer above. You need to understand that the moment the elseif statement is executed, the statement becomes true, so the code never jumps to the next line.

var number = 15

var three = (number)%3 three

var five = (number)%5 five

if five == 0 && three == 3 { println("BuzzFizz") } else if five == 0 { println("Buzz") } else if three == 0 { println("Fizz") }

john dev.
john dev.
Courses Plus Student 1,935 Points

Yes, you are right!

john dev.
PLUS
john dev.
Courses Plus Student 1,935 Points
john dev.
john dev.
Courses Plus Student 1,935 Points

Hello Giulio Autelitano. I am "sorry" if I misunderstood you. Here is my solution for your problem. I hope it helps you! : )

var three = 3 // choose a number

var five = 0 // choose a number

if five == 0 && three == 3 {

println("BuzzFizz") }

else if five == 0 {

println("Buzz") }

else if three == 0 {

println("Fizz") }

john