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ISAIAH S
1,409 PointsWhy isn't this working?? String number = console.readLine("Enter your favorite number: "); if(number.isLetter())...
Code:
import java.io.Console;
public class Isaiah {
public static void main(String[] args) {
Console console = System.console();
String isName = console.readLine("Enter your name: ");
String fatal = "";
if (isName.equals("*ISAIAH*")) {
String secretCode =console.readLine("YOU HAVE ENTERED A SECRET CODE.\nHERE ARE YOUR OPTIONS.\n >IF YOU WANT TO CONTINUE:\nPRESS I.\n >IF YOU WANT TO EXIT:\n PRESS E.\n ");
if (secretCode.equalsIgnoreCase("E")) {
System.exit(0);
} else if (secretCode.equalsIgnoreCase("I")) {
fatal = console.readLine(" WARNING:\nTHIS PROGRAM CAN BE FATAL.\nDO YOU STILL WANT TO CONTINUE?\n\n ");
if(fatal.equalsIgnoreCase("yes")) {
console.readLine("Hello, %s.\n", isName);
} else {
System.exit(0);
}
}
}
String number = console.readLine("Enter your favorite number: ");
if (number.isLetter()) {
throw new IllegalArgumentException("A number is required.");
}
String mood = console.readLine("Enter your favorite mood: ");
String creature = console.readLine("Enter your favorite creature: ");
String color = console.readLine("Enter your favorite color: ");
String lotsOfStuff = mood;
lotsOfStuff = lotsOfStuff.toLowerCase();
String moreLotsOfStuff = color;
moreLotsOfStuff = moreLotsOfStuff.toLowerCase();
String evenMoreLotsOfStuff = number;
evenMoreLotsOfStuff = evenMoreLotsOfStuff.toLowerCase();
String evenEvenMoreLotsOfStuff = creature;
evenEvenMoreLotsOfStuff = evenEvenMoreLotsOfStuff.toLowerCase();
String isFavoriteThing = console.readLine("Is a %s, %s %s year old %s your favorite thing? ", lotsOfStuff, moreLotsOfStuff, evenMoreLotsOfStuff, evenEvenMoreLotsOfStuff);
if (isFavoriteThing.equalsIgnoreCase("no")) {
console.readLine("Why not? ");
console.printf("Well you should, it's all of your favorite stuff.\n\n");
}
String computer = console.readLine("-------------------------------------------------\n\n Do you want to have a talk with the computer? ");
console.printf("\n---------------------------------------------\n\n\n");
String howYouDoing = "";
if(computer.equalsIgnoreCase("yes")) {
howYouDoing = console.readLine("Hello %s, how are you doing?\n ", isName);
if(howYouDoing.equalsIgnoreCase("sad")) {
console.readLine("Why are you %s, %s? \n", howYouDoing, isName);
}
}
}
}
Error:
Isaiah.java:15: error: cannot find symbol
if(number.isLetter()){throw new IllegalArgumentException("A number is required.");}
^
symbol: method isLetter()
location: variable number of type String
1 error
1 Answer
qlpxjevhuv
10,503 PointsYou are getting an error because your number variable is of type String. The [isLetter](http://docs.oracle.com/javase/7/docs/api/java/lang/Character.html#isLetter(char\)) method is part of the Character class.
If you want to check whether a digit is present within your string, I recommend you use the [matches](http://docs.oracle.com/javase/7/docs/api/java/lang/String.html#matches(java.lang.String\)) method. Here is an example:
public class Introductions {
public static void main(String[] args) {
String number = "1";
String words = "Hello!";
if (number.matches("\\d")) {
System.out.println("Success!");
}
if (words.matches("\\d")) {
System.out.println("Oh, no!");
}
}
}
ISAIAH S
1,409 Pointscan I make isLetter be of type string?
Robert Richey
Courses Plus Student 16,352 PointsRobert Richey
Courses Plus Student 16,352 PointsHi Isaiah,
Fixed markdown for the posted code. If you're curious about how to add markdown like this on your own, checkout this thread on posting code to the forum . Also, there is a link at the bottom called Markdown Cheatsheet that gives a brief overview of how to add markdown to your posts.
The language specifier had a dot (".") in front of it, preventing syntax highlighting and none of the code was indented, making it very difficult to read.
Cheers!