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Python Comparison Solution

Posted by Oleg Tiger
Oleg Tiger
388 Points

why it didn't work???

name = input("Please enter your name: ") number = int(input("Please enter a number: "))

print("Hi {}".format(name)) print("Your number is {}".format(number))

is_fizz = number % 3 == 0 is_buzz = number % 5 == 0
is_fizzbuzz = number % 3 == 0 and number % 5 == 0

if number == is_fizz: print("{} is a fizz number".format(number)) elif number == is_buzz: print("{} is buzz number".format(number)) elif number == is_fizzbuzz: print("{} is a fizzbuzz".format(number)) else : print("{} not fizz and not buzz".format(number))

1 Answer

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,967 Points
KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,967 Points

is_fizz, is_buzz, and is_fizzbuzz are boolean values and all you need for your if statements

name = input("Please enter your name: ")
number = int(input("Please enter a number: "))

print("Hi {}".format(name))
print("Your number is {}".format(number))

is_fizz = number % 3 == 0
is_buzz = number % 5 == 0
is_fizzbuzz = number % 3 == 0 and number % 5 == 0

if is_fizzbuzz:
  print("{} is a fizzbuzz".format(number))
elif is_fizz:
  print("{} is a fizz number".format(number))
elif is_buzz:
  print("{} is buzz number".format(number))
else:
  print("{} not fizz and not buzz".format(number))

Note: You should also check for is_fizzbuzz first to avoid false positives. For example 15 meets the condition of all three but should be recorded as a fizzbuzz number.