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Marzoog AlGhazwi15,796 Points
why it work with the '8' but with it didn't ??!
Can any one expline why its working that way !
import re string = '1234567890' good_numbers = re.findall(r''' \d [^5678]+ ''', string, re.X)
Steven Parker217,545 Points
The "\d" token matches any digit, so without the "8" you get two pieces, "1234" and then "7890" because it "7" is matched by the "\d".
But when you add "8" to the excluded digits, then "7890" no longer matches, so you get "890" where the "8" matches the "\d":.
A more conventional solution might use just one character class without the "any digit" preceding it.