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Hoang Le
Courses Plus Student 1,274 Pointswhy my code is not working
var html = '';
var rgbColor;
function randomNumber() {
return Math.floor(Math.random() * 256);
}
function randomColor() {
var color = "rgb(";
color += randomNumber + ",";
color += randomNumber + ",";
color += randomNumber + ")";
return color;
}
function print(message) {
document.write(message);
}
for (var i = 1; i < 50; i ++ )
{
rgbColor = randomColor();
html += '<div style="background-color:' + rgbColor + '"></div>';
}
print(html);
I don't why it is not working....
Hoang Le
Courses Plus Student 1,274 Pointsthank you " Dragomir" got it
1 Answer
Steven Parker
230,274 PointsYou named the function instead of invoking it.
In randomColor, when you call your randomNumber function, you forgot the parentheses after the function name:
color += randomNumber + ","; // <-- this only NAMES the function
color += randomNumber() + ","; // <-- this correctly CALLS the function
Dragomir Dan
Courses Plus Student 1,367 PointsDragomir Dan
Courses Plus Student 1,367 PointsIn the function randomColor when you call randomNumber ... the random number is a function not a variable .
function randomColor() { var color = "rgb("; color += randomNumber() + ","; color += randomNumber() + ","; color += randomNumber() + ")"; return color; }