Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Hoang Le
Courses Plus Student 1,274 Pointswhy my code is not working
var html = '';
var rgbColor;
function randomNumber() {
return Math.floor(Math.random() * 256);
}
function randomColor() {
var color = "rgb(";
color += randomNumber + ",";
color += randomNumber + ",";
color += randomNumber + ")";
return color;
}
function print(message) {
document.write(message);
}
for (var i = 1; i < 50; i ++ )
{
rgbColor = randomColor();
html += '<div style="background-color:' + rgbColor + '"></div>';
}
print(html);
I don't why it is not working....
Hoang Le
Courses Plus Student 1,274 Pointsthank you " Dragomir" got it
1 Answer
Steven Parker
231,275 PointsYou named the function instead of invoking it.
In randomColor, when you call your randomNumber function, you forgot the parentheses after the function name:
color += randomNumber + ","; // <-- this only NAMES the function
color += randomNumber() + ","; // <-- this correctly CALLS the function
Dragomir Dan
Courses Plus Student 1,367 PointsDragomir Dan
Courses Plus Student 1,367 PointsIn the function randomColor when you call randomNumber ... the random number is a function not a variable .
function randomColor() { var color = "rgb("; color += randomNumber() + ","; color += randomNumber() + ","; color += randomNumber() + ")"; return color; }