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# why second output is NONE? def add_two(num): val = num + 2 print(val) print (add_two(10))

tell me please why first output is 10(right) and second is NONE?

def add_two(num): val = num + 2 print(val)

print (add_two(10))

def add_two(num): val = num + 2 print(val)

print (add_two(10))

RESULT IS...

treehouse:~/workspace\$ python functions.py
12
None

why None???

## 6 Answers

When a function doesn't have a return statement the default return value is None. The following will print 12 in both cases.

```def add_two(num):
val = num + 2
print(val)
return val

print(add_two(10))
```

print(add_two(10))

```# ====> in global scope.
# ====> When a function doesn't have a return
# statement the default return value is None.
def print_name():
print('Ary de Oliveira')

def print_favorite_name():
print('Ary')

numero = 120

def set_numero():
numero = 60
key = 'a'
print(key)

print(set_numero())
print(numero)
print_name()
print_favorite_name()

my_var = 10
def multiply():
my_var = 10 * 2
print(my_var)
#ary
```

Please tell me what you passed in as an argument for add_two() when it outputted 'None'.

print(add_two(10))

This has already been answered. Your add_two() function returns None because it has no explicit return statement. As a result print(add_two(10)) displays None.

thanks guys!!