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JavaScript

Posted by Jia Tang
Jia Tang
Courses Plus Student 49 Points

Why the console runs "console.log(name); on line 14 first than line 12?

When you first show us the console of this file, we can see "Andrew" ion line 14 runs before Joel Kraft on line 12. I am wondering whats the reason of this.

christopher abramson
christopher abramson
22,741 Points
christopher abramson
christopher abramson
22,741 Points

Give us an example of the code please, and we'll see if we can help!

Jia Tang
Jia Tang
Courses Plus Student 49 Points

<html> <head> <title>name - let and Const</title> </head> <body> <h1>Name</h1> <script> var name = "Andrew";

  function createFullName(fName, lName) {
      name = fName + " " + lName;
      console.log(name);
  }
  console.log(name);
  createFullName("Joel", "Kraft");
</script>

</body> </html>

So the above is the original code, and if you run the console you are likely see what I am confused with (I am a beginner of JS)

2 Answers

Steven Parker
Steven Parker
243,656 Points
Steven Parker
Steven Parker
243,656 Points

It's the difference between declaring and calling a function.

When you declare a function, you're only telling the computer what to do later when you call that same function. It doesn't happen yet.

So the code inside the function only runs when the function is called on line 15.

Dragomir Dan
PLUS
Dragomir Dan
Courses Plus Student 1,367 Points
Dragomir Dan
Dragomir Dan
Courses Plus Student 1,367 Points

You declare the variable name with the value of "Andrew" and you console log the name and then you execute the function that will print out Joel Kraft