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Start your free trial###### Arun Patel

1,180 Points# Why the function didn't return right answer?

I executed same code separately and got right answer (25)

def squared(x): try: x = int(x) y = x * x return y except ValueError: x = str(x) z = x + x return z

def test(): x = squared(5) print(x)

test()

```
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(x):
try:
x = int(x)
y = x * x
return y
except ValueError:
x = str(x)
y = x + x
return y
```

## 1 Answer

###### Katie Wood

19,140 PointsHello there,

You're close - the only thing not functioning correctly is when it passes a string value. With the way it works right now, using x + x, it will just print the string twice. However, it is supposed to print the string a number of times equal to the strings length, so it should instead be x * len(x). With that one line changed, it looks like this:

```
def squared(x):
try:
x = int(x)
y = x * x
return y
except ValueError:
x = str(x)
y = x * len(x)
return y
```

If you have things spaced out to make it easier to read as you're learning, that's totally fine. If you're interested, though, this can be shortened a good bit:

```
def squared(x):
try:
return int(x) * int(x) #can also do int(x) ** 2 (exponent notation)
except ValueError:
return x * len(x)
```

###### Arun Patel

1,180 PointsThanks a lot for the clarification.

## Anibal Marquina

9,523 Points## Anibal Marquina

9,523 Points