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JavaScript JavaScript Array Iteration Methods Array Manipulation Remove Array Items with filter()

Posted by ammarkhan
.a{fill-rule:evenodd;}techdegree
ammarkhan
Front End Web Development Techdegree Student 21,661 Points

Why this code won't work?

I am trying the following

const numbers = [1,2,3,4,5,6,7,8,9,10];
const no2 = numbers.filter( (number)=> {number !== 2});

console.log(no2);

it returns an empty array, but when I do

const numbers = [1,2,3,4,5,6,7,8,9,10];
const no2 = numbers.filter( number=> number !== 2);
console.log(no2);

it return the array without 2, why brackets make such a difference and what?

1 Answer

ven dev
ven dev
8,292 Points
ven dev
ven dev
8,292 Points

When you use brackets you need to return the value.

Without the brackets the value after the arrow gets returned by default.

const numbers = [1,2,3,4,5,6,7,8,9,10];

// This will work
numbers.filter( (number)=> { return number !== 2});
numbers.filter( (number)=>  number !== 2);

// This wont work
numbers.filter( (number)=> { number !== 2});