Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

JavaScript JavaScript Array Iteration Methods Combining Array Methods Working with Objects in Arrays

Umidjon Khaitov
Umidjon Khaitov
8,872 Points

Why user.name and user[name] are not same in these conditions?

Hello there, Why these are not giving same results? I even thought user[age] is more likely reliable, but kind of feel confused here. Many thanks in advance.

const newUsersArray = users.filter(user => user.name !== 'Samir');
const newUsersArray = users.filter(user => user[name] !== 'Samir');

1 Answer

Dmitry Polyakov
Dmitry Polyakov
4,961 Points

I believe you must use quotes around name

user["name"]

Umidjon Khaitov
Umidjon Khaitov
8,872 Points

Thank you Dmitry, I thought, I was accessing user.name as a variable, as you know, when you access object properties, assuming as a variable . obj[key] , we don't need to wrap up with quotes if we access as a variable in the property. That thing confused me, Anyways, Spasibo)