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Python Python Collections (2016, retired 2019) Slices Slice Functions

Why won't my iterable function work?

To me, line by line, this is 1) Creating a function with the iterable variable. 2) Getting input in the form of a list for the iterable variable. 3) Creating a copy of the iterable list with only items 1-4. 4) Returning the copy of the iterable list, which only has items 1-4 in it. I don't understand why this doesn't work.

def first_4(iterable):
    iterable = list(input("Input something. "))
    first_4_items = iterable[:4]
    return first_4_items

2 Answers

Steven Parker
Steven Parker
229,645 Points

The iterable is passed to your function as an argument. You won't need to "input" anything!

David Lahoud
David Lahoud
1,408 Points

You just need to return the slice iterable not take input a solution for your code would look something like this: def first_4(iterable): return iterable[0:4]

and to check you can call the function and add different info into the parameters like so: first_4([1,2,3,4,5,6])