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Srikanth Srinivas
1,465 PointsWhy won't this script return all the words in the list?
I just get two values in my dictionary if i enter more than 3 words in the any string argument
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.
def word_count(anystring):
my_dict = {}
my_list = anystring.split()
for word in my_list:
my_dict[my_list.count(word)] = word
return my_dict
1 Answer
Martin Cornejo Saavedra
18,132 PointsYou have one definition backwards. The keyword is the word and the value is the count. I added an if to skip repeated words, this way the code is more efficient.
def word_count(anystring):
my_dict = {}
my_list = anystring.split()
for word in my_list:
if word not in my_dict:
my_dict[word] = my_list.count(word) #I changed the error here
return my_dict